Question 406566
a){{{sinA/a = sinC/c}}} ==>  {{{sinC = (c/a)sinA = 4*sin 45 > 1}}}.  So 0 triangles.

b)  {{{sinB/b = sinC/c}}}==>  {{{sinC = (c/b)sinB  = 0.995 < 1}}}, so there could be one or two triangles.

c) {{{sinA/a = sinC/c}}} ==>  {{{sinA = (a/c)sinC > 1}}}.  So 0 triangles.

d) {{{sinA/a = sinB/b}}} ==>  {{{sinB = (b/a)sinA =  1}}}, and there's exactly 1 triangle ( a right triangle!).