Question 406473
how does one solve: x^2-13x+42=0  
  
Here is what I have so far:  Subtract 42 from both sides.  Divide -13 by 2 and square -6.5 to get 42.25.  Add 42.25 to both sides.  Now my equation is 
x^2-13x+42.25=0.25 
  Now, how can I factor out the equation to solve it? 
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{{{(x - 6.5)^2 = 0.5^2}}}
x - 6.5 = ± 0.5
x = 6, 7
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x^2-13x+42=0
(x-6)*(x-7) = 0
x = 6, 7