Question 5476
take the first equation:
x+5y=5 and put it in terms of x by subtracting 5y from both sides:
x=5-5y
then use the second equation and substitute 5-5y in for x
3x+15y=-1
3(5-5y)+15y=-1
eliminate the parentheses, consolidate like terms and solve for y:
15-15y+15y=-1
15=-1
This is not a true statement, so no solution exists. (These are parallel lines and never cross, therefore they don't have an intersection)