Question 406255
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Hi
*[tex \large\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
y = (1/9)x+2  |slope of  &#8869; line would be -9 (negative reciprocal of 1/9 )
New Line
 y = -9x + b  |using ordered pair Pt(3,-3) mto solve for b
-3 = -27 + b
 24 = b
 y = -9x + 24