Question 406030
find polar coordinates of each point (-2sqrt3,2)
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The point is in the 2nd quadrant.
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theta = tan^-1(2/(-2sqrt(3)) = tan^-1(-1/sqrt(3)) = (5pi/6)
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r = sqrt[(2sqrt(3))^2 + 2^2] 
= sqrt[12+4]
= 4
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polar coordinates: (4,5pi/6)
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Cheers,
Stan H.