Question 405756
A normal distribution consists of 100 scores with a mean of 60 and a standard deviation of 5. Approximately how many scores are above 70 (round off to the nearest whole number)? 

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z(70) = (70-60)/5 = 2
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P(70 < x <= 100) = P(z > 2) = normalcdf(2,1000) 
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= 0.0228
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That's a fraction of percentage.
The number of scores is approximately 0.0228(100) = 2.28
Rounding down the number of scores is 2.
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Cheers,
Stan H.
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