Question 405751
A teacher finds that the mean score of his class is 82 with a standard deviation of 6. Find the probability that a student will have a score between 82 and 88.
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z(82) = (82-82)/6 = 0
z(88) = (88-82)/6 = 1
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P(82 < x < 88) = P(0 < z < 1) = 0.3413
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Cheers,
Stan H.
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