Question 405417
It depends on the parameter {{{alpha}}} that you use.

The probability mass function for the Poisson distribution is {{{p(x) = e^(-alpha)*(alpha^x/x!)}}}.  The parameter  {{{alpha = 2}}} is correct.
The probability of catching 0, or 1, or 2 fish is {{{ e^(-2)*(2^0/0!) +  e^(-2)*(2^1/1!) + e^(-2)*(2^2/2!) }}}.  Hence the probability of catching at least 3 fish is {{{1 -( e^(-2)*(2^0/0!) +  e^(-2)*(2^1/1!) + e^(-2)*(2^2/2!))= 5e^(-2) = 0.676676 }}}, to 6 decimal places.