Question 405271

{{{y-(14/y) = 5}}}...multiply by {{{y}}} 


{{{y*y-(14/y)y = 5y}}}


{{{y^2-(14/cross(y))cross(y) = 5y}}}


{{{y^2-14 = 5y}}}


{{{y^2-5y -14 = 0}}}........replace {{{-5y}}} with {{{2x-7y}}}


{{{y^2 +2y -7y -14 = 0}}}.....Group the first two terms together and the last two terms together like this:


{{{(y^2 +2y) +(-7y -14) = 0}}}


{{{y(y +2) -7(y+2) = 0}}}......


{{{(y -7)(y+2) = 0}}}.