Question 404904
write an equation of the line with slope = 7/8 and containing the point (6,3)
:
Use the point/slope formula: y - y1 = m(x-x1)
m = 7/8; x1 = 6, y1 = 3
:
y - 3 = {{{7/8)}}}(x - 6)
:
y - 3 = {{{7/8)}}}x - 6*{{{7/8}}}
:
y - 3 = {{{7/8)}}}x - {{{42/8}}}
:
y - 3 = {{{7/8)}}}x - {{{21/4}}}
Add 3 to each side
y = {{{7/8)}}}x - {{{21/4}}} + 3
:
y = {{{7/8)}}}x - {{{21/4}}} + {{{12/4}}}
:
y = {{{7/8)}}}x - {{{9/4}}}; is the equation
:
:
Check this, replace x with 6, find y
y = {{{7/8)}}}6 - {{{9/4}}}
y = {{{42/8)}}}x - {{{9/4}}}
y = {{{21/4)}}} - {{{9/4}}}
y = {{{12/4}}} = 3, confirms our equation