Question 404983
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Hi, Previously posted.
*[tex \large\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
y = 3/2x -5  | y-intercept is Pt(0,-5)
Plotting that point and using slope = 3/2 to find at least one more Pt(2,-2)
Note: as y increases/decreases by 3, x increases/decreases by 3
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(0, -5,0.3),
circle(2, -2,0.3),
graph( 300, 300, -6, 6, -6, 6,0,1.5x-5))}}}