Question 404974
  <pre><font size = 3 color = "indigo"><b>
Hi
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p= .10 & q = .90
nCx = {{{n!/(x!(n-x!))}}}
P(exactly one defect in a random sample of 5 ) = 5(.10)^1(.90)^4 = .3281
P(no defects in a random sample of 5)= 1(.90)^5 = .5905