<PRE><B>Question 404675</B>
&lt;br&gt;&lt;font face=&quot;Tahoma&quot;&gt;If the function you are asking about is &lt;br&gt;

{{{f(x)=(4/3)*x+5}}}&lt;br&gt;

then it is easy to see that there are no possible discontinuities.&lt;br&gt;

When we speak of discontinunities, we are looking for values of x where f(x) is not defined.&lt;br&gt;

The best examples of these are when you end up with zero in the denominator, or when you have the square root of a negative number.&lt;br&gt;

So without any visible discontinuities, we can see that the domain of f(x) is ALL REAL NUMBERS.&lt;br&gt;

The range of f(x) is also ALL REAL NUMBERS for the same reasoning.&lt;br&gt;

However, if the function is {{{f(x)=4/(3x)+5}}}&lt;br&gt;

then we can see a potential discontinuity when x=0&lt;br&gt;

When x=0, we have 0 in the denominator which is not allowed.&lt;br&gt;

So the domain of that function would be ALL REAL NUMBERS except 0.&lt;br&gt;

The range of that function would be ALL REAL NUMBERS except 5.&lt;br&gt;

When you ask a question, be very careful of how you &quot;group&quot; the variables and numbers.&lt;br&gt;

From the original question, it is hard to tell if the function you are asking about is&lt;br&gt;

{{{f(x)=(4/3)*x+5}}}  or   {{{f(x)=4/(3x)+5}}}&lt;br&gt;

I hope this helps!   :)&lt;br&gt;</PRE>