Question 404753

find the slope intercept form of the equation of the line that passes thought ({{{-1,5}}})and is {{{parallel}}} to {{{4x+2y=8}}}

first find the slope of this line:

{{{4x+2y=8}}}......write it in slope-intercept form...or solve for {{{y}}}

{{{2y= - 4x + 8}}}.......both sides divide by {{{2}}}

{{{2y/2= - 4x/2 + 8/2}}}

{{{y= -2x + 4}}}.........as you can see, slope is {{{-2}}}

since the line that passes thought ({{{-1,5}}}) is {{{parallel}}} to given line, should have {{{same}}} slope

now, we have slope {{{m=-2}}} and point ({{{-1,5}}}) and we can find the equation of the line that passes thought


*[invoke find_line_by_slope_and_point -1, 5, -2]


now, let see a graph with both lines on it:

{{{y= -2x + 4}}}

{{{y=-2x+3}}}


{{{ graph( 500,500, -10, 10, -10, 10, -2x + 4,-2x+3) }}}