Question 404719
A small feeder airline knows that the probability is .10 that a reservation holder will not show up for its daily 7:15 A.M. flight into a hub airport.
The flight carries 10 passengers. 
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Binomial Problem with n = 10, p(not show) = 0.1 ; p(show) = 0.9
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(a) If the flight is fully booked, what is the probability that all those with reservations will show up?
:::(0.9)^10 = 0.3487
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(b) If the airline overbooks by selling 11 seats, what is the probability that no one will have to be bumped? 
P(no bump) = P(0<= show <=10) = 1 - binomcdf(11,0.9,10) = 0.3138
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(c) That more than one passenger will be bumped?
P(2<= bumped <=10) = 1 - binomcdf(10,0.1,1) = 0.2639
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Cheers,
Stan H.
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(d) The airline wants to overbook the flight by enough
seats to ensure a 95 percent chance that the flight will be full, even if some passengers may be
bumped. How many seats would it sell?