Question 404701
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Hi
solving:
18x+27x^2+3 = 0   |Assuming for 'solving' expression is = to zero
 3(9x^2 + 6x + 1)= 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-6 +- sqrt( 36-36))/(2*9) }}} 
 x = -6/18 = -1/3

CHECKING our Answer***
-6 + 3 + 3 = 0