Question 404691
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Hi
two consecutive integers
Let x and (x+1) represent the two consecutive integers
Question states***
 x +(x+1)= x(x+1)-19
Solving for x
 2x + 1 = x^2 + x - 19
  x^2 -x - 20 = 0 
factoring
 (x-5)(x+4)= 0 Note:SUM of the inner product(-5x) and the outer product(4x) = -x
(x-5)=0   x = 5, the two consecutive integers are 5 and 6
(x+4)= 0  x = -4 the two consecutive integers are -4 and -3

CHECKING our Answer(s)***
 5 + 6 = 30 - 19
 -4 - 3 = -4*-3 - 19