Question 404571
Given:
Let {{{A}}} = A's age now
Let {{{B}}} = B's age now
Then {{{B-2}}} = B's age 2 years ago
given:
(1) {{{A = 2*(B - 2)}}}
(2) {{{A - B = 6}}}
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from (1):
(1) {{{A = 2B - 4}}}
(1) {{{A - 2B = -4}}}
(1) {{{-A + 2B = 4}}}
Now add (1) and (2)
(1) {{{-A + 2B = 4}}}
(2) {{{A - B = 6}}}
{{{B =10}}}
And, from (2),
(2) {{{A - B = 6}}}
(2) {{{A - 10 = 6}}}
(2) {{{A = 16}}}
A is 16 now
check answer:
(1) {{{A = 2*(B - 2)}}}
(1) {{{16 = 2*(10 - 2)}}}
(1) {{{16 = 2*8}}}
{{{16 = 16}}}
OK