<PRE><B>Question 404543</B>
 In how many ways can 9 instructors be assigned to six sections of a course in mathematics? 
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Mr Kmr is correct. I tried it with 
3 instructors and 2 sections and
the number was 6 = 3P2 = 3!/(3-2)! 
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Let the sections pick the instructors:
Ans: 9P6 = 9!/(9-6)! = 9!/3! = 9*8*7*6*5*4 = 60480
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Cheers,
Stan H.</PRE>