Question 404328
Given the function f(x)= 3x^2+8x-6. Calculate the following values:
f(x+1) and f(-x)
:
f(x+1) = 3(x+1)^2 + 8(x+1) + 6
f(x+1) = 3(x^2+2x+1) + 8x + 8 + 6
f(x+1) = 3x^2 + 6x + 3 + 8x + 14
f(x+1) = 3x^2 + 14x + 17
:
f(-x) = 3(-x)^2 + 8(-x) + 6
f(-x) = 3x^2 - 8x + 6