Question 43586
{{{y >= sqrt(3x + 12)}}}
*sorry, the graph doesn't extend all the way to (-4,0)
{{{ graph( 600, 600, -10, 10, -10, 10, sqrt(3x + 12) ) }}}
Limitation To Domain:
A real number squared will not give you a negative number, so:
{{{3x + 12 >= 0}}}
{{{3x >= -12}}}
{{{x >= -4}}}
Vertex: (-4,f(x)) = (-4,0)
Shading:
If you pick the point: (-4,1)
You get: {{{1 > 0}}} which is correct
You would shade only above the solid line, not to the left or under it.
If it helps you, you can draw a vertical line at {{{x = 4}}}. Shade above the graphed square root line and to the right of the vertical line.