Question 404436
If log a=6 and log b=3, 
what is the numerical value of 
log (cubed root)of ab^4 ?
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= (1/3)log(ab^4)
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= (1/3)[log(a) + 4*log(b)]
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Substitute to get:
= (1/3)[6 + 4*3]
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= (1/3)(18)
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= 6
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Cheers,
Stan H.
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