Question 404380
2x over x^2+6x+8 = x over x+4 minus 2 over x+2 
(i hope the way i wrote it is not confusing. i'm sorry!) 
I have gotten this far. 2x=x^2+2x-2x+4
2x=x^2+4 
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(2x)/(x^2+6x+8)= x/(x+4) - 2/(x+2)
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Multiply thru by x^2+6x+8 to get:
2x = x(x+2) - 2(x+4)
2x = x^2+2x-2x-8
x^2-2x-8 = 0
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Factor:
x^2-4x+2x-8 = 0
x(x-4)+2(x-4) = 0
(x-4)(x+2) = 0
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x = 4 or x = -2
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x cannot be -2 as that would make the denominator (x+2) = zero.
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So, x = 4 is the only valid answer.
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Cheers,
Stan H.
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