Question 404141
{{{((r^2+5r)/(r^2+4r-5))/(r/(r+1))}}}
Let's see, we will go thru it step-by-step
:
Invert the dividing fraction and multiply
{{{((r^2+5r)/(r^2+4r-5))}}} * {{{(r+1)/r}}}
:
Factor
{{{(r(r+5))/((r+5)(r-1)))}}} * {{{(r+1)/r}}}
:
Cancel (r+5) and r, leaving
{{{1/((r-1))}}} * {{{(r+1)}}} = {{{((r+1))/((r-1))}}}; so you're absolutely right, way to go.
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:
But I am not sure about, what's meant here;
(r^2+5r)(r+1)=(r+5)(r+1)=r+1*x(x+5)
(r^2+4r-5)=(r+5)(r-1)r=r-1*x(x-5)
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How did x get in there?