Question 404300
Suppose z varies directly as x and inversely as the square of y. When x = 35 and y = 7, the value of z is 50. Choose the function that models this relationship; and find the value of z when x = 5 and y = 10. 
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z = k*x/y
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Solve for "k" using "When x = 35 and y = 7, the value of z is 50."
50 = k*35/7
k = 10
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Equation for this problem: 
z = 10x/y
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Find the value of z when x = 5 and y = 10.
z = 10*5/10
z = 5
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Cheers,
Stan H.