Question 404193
 FIND THE AREA OF A TRIANGLE WHOSE VERTEX IS AT THE MIDPOINT OF AN UPPER EDGE OF A CUBE OF EDGE A,
 AND WHOSE BASE MEET WITH DIAGONALLY OPPOSITE EDGE OF A CUBE.
:
The base will also be A
:
The height will = the diagonal inside the cube
h = {{{sqrt(2A^2)}}}
Area of triangle = {{{1/2}}}* A *{{{sqrt(2A^2)}}}