Question 403981
A water flow restrictor has reduced the flow of water to 2 gal/min.
 This amount is 1 gal/min less than three-fifths the original flow rate.
 Find the original rate.
:
Let r = the original rate of flow
:
{{{3/5}}}r - 1 = 2
{{{3/5}}}r = 2 + 1
{{{3/5}}}r = 3
Multiply both sides by 5
3r = 5(3)
3r = 15
r = {{{15/3}}}
r = 5 gal/min was the original flow