Question 403937
{{{(1/5)x=sqrt(2x-25)}}} /^2 both sides of equation
{{{(1/25)x^2=2x-25}}} multiply both sides by 25
{{{X^2-50x+625=0}}}
 {{{x = (-(-50) +- sqrt( (-50)^2-4*1*625 ))/(2*1) }}} 
 {{{x = (50 + sqrt( 0))/2 }}} 
{{{x=25}}}
In this type of equations you always have to check answer
Put x=25 in equation
{{{1/5*25=sqrt(2*25-25)}}}
{{{5=sqrt(25)}}}
{{{5=5}}} correct
Answer 25