Question 403882
{{{(x^2+2x-15)/(x+5)}}} = {{{(x^2+2x+3x-3x-15)/(x+5)}}} = {{{(x^2+5x-3x-15)/(x+5)}}} =  {{{(x^2+5x-(3x+15))/(x+5)}}} = {{{(x(x+5)-3(x+5))/(x+5)}}} = {{{((x+5)*(x-3))/(x+5)}}}
if x no equals -5, then x= -3