Question 403877
Just to clarify, is this your question?


{{{6(p^2 -1)=5p}}}


If so, here's how you do it:


{{{6(p^2 -1)=5p}}}

First, get rid of the brackets by distributing the 6:
{{{6p^2 -6)=5p}}}

Next, subtract 5p from both sides, so that the right side is zero:
{{{6p^2 - 6 - 5p = 0}}}

Rearrange so that it is in standard form:
{{{6p^2-5p-6=0}}}


To solve this, you can either factor it (which is a pain!) or use the Quadratic Formula.


If you factor it, you will end up with:
(2p-3)(3p+2) = 0
p=3/2 or p=-2/3


If you use the Quadratic Formula:

{{{p = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{p = (5 +- sqrt( (-5)^2-4*6*(-6) ))/(2*6) }}}
p=3/2 or p=-2/3


So as you can see, you get the same answer whether you factor it or use the quadratic formula.


Check out this link for a graph of the function: http://www.wolframalpha.com/input/?i=6p^2-5p-6%3D0


Hope this helps!