Question 403854
 ln x + ln (x+3) = 1
I first combined the ln
ln [x(x+3)] = 1
ln x (squared) + 3x = 1
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{{{ln(x^2 + 3x) = 1 = ln(e)}}}
{{{x^2 + 3x = e}}}
{{{x^2 + 3x - e = 0}}}
e is a constant, ~2.71828
Solve the quadratic for x
*[invoke solve_quadratic_equation 1,3,-2.71828]