Question 43551
By looking at the line, it looks like: {{{y = (2/3)x + 1}}}
Pick Two Points: (0,1) and (3,3)
Slope(M) = (y2 - y1)/(x2 - x1) = (3 - 1)/(3 - 0) = 2/3
Y-intercept: (0,1)
Use slope-intercept form:
{{{y = mx + b}}} where {{{m}}} is the slope and {{{b}}} is the y-intercept
{{{y = (2/3)x + 1}}}