Question 403704
{{{2x+3y<=6}}}

{{{3y<=-2x+6}}}

{{{y=(-2x/3+2)

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For plotting the graph you need the boundary 
so let {{{2x+3y=6}}}
x=0,y=2(0,2)

y=0,x=3(3,0)

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The boundary
plot the points and draw the line
{{{drawing(300,300,-5,5,-5,5,circle(0,2,0.2),circle(3,0,0.2),graph(300,300,-5,5,-5,5,y=(-2x/3)+2))}}}

Since y is less than something all points below the line are solutions to the equation. The shaded area

{{{graph(300,300,-5,5,-5,5,y<=(-2x/3)+2))}}}