Question 403546
The 1st is 1 of 49.
Then 1 of 48, 47, 46, etc, since the numbers don't repeat (ie, you can't have 2 35's).
--> 49*48*47*46*45*44 = a big number
Since order doesn't matter, there are 6 chances to pick any particular, so the big number is divided by 6*5*4*3*2*1 = 720
The # of combinations = 13983816
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This is 49!/(43!*6!), or 49C6