Question 43526
Let's see...you want to simplify:
{{{(9y^2/(x^(-8)*y^0))^(1/2)}}}

Your first step is correct:{{{y^0 = 1}}}, so now yu have:
{{{(9y^2/x^-8)^(1/2)}}}
Your second statement is also correct:{{{x^(1/2) = sqrt(x)}}}.
So now you want to multiply the internal exponents by the external exponent:
{{{(9^(1/2)*(y^2)^(1/2))/(x^-8)^(1/2)}}} Simplify this. For the numerator:{{{9^(1/2) = sqrt(9)}}} = 3 and {{{(y^2)^(1/2) = sqrt(y^2)}}} = y
And for the denominator: {{{(x^(-8))^(1/2) = x^(-4)}}}
{{{3y/x^-4}}} Now bring the denominator up and change the sign of the exponent.
{{{3x^4y}}}