Question 403285
If L is the length, W is the width
Perimeter of the rectangle is {{{P=2(L+W)}}}, so {{{2(L+W)=76}}}.
If the width be double (2W) and the length ne increase by 5 m (L+5)? the perimeter will be {{{2(2W+(L+5))=120}}}
Equation system
{{{2(L+W)=76}}}
{{{2(2W+(L+5))=120}}}
.
{{{L+W=38}}}
{{{L+2W+5=60}}}
.
{{{L+W=38}}}
{{{L+2W=55}}} From the second equation we subtract the first equation
.
{{{L+W=38}}}
{{{W=17}}}
If {{{W=17}}} from the first equation will have {{{L=38-W=38-17=21}}}
So the length is 21m and the width is 17m