Question 403229
I'll do one of each of the two types of problems
and leave the rest to you.
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Find the mean of the distribution shown.
x 0 3 5
P(x) 0.36 0.40 0.24
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To determine the mean:
1st: Multiply each x value by its probability
2nd: Add the products to get the mean
x-bar = 0*36 + 3*0.40 + 5*0.24
x-bar = 0 + 1.2 + 1.2
x-bar = 2.4
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The following distribution is not a probability distribution because
x -5 -4 -3 -2 -1
P(x) 0.11 0.16 0.42 0.16 0.30
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Rules:
1st: Each probability must be between 0 and 1
2nd: The sum of the probabilities must be 1.
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Your Problem: The sum is > 1 so this is not a probability distribution.
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Cheers,
Stan H.
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The following distribution is not a probability distribution because
x -5 -4 -3 -2 -1
P(x) 0.20 0.20 –0.23 0.54 0.29 
Find the mean of the distribution shown.
x 1 2
P(x) 0.46 0.54 
Find the mean of the distribution shown.
x -3 -2 -1 0
P(x) 0.19 0.24 0.40 0.17 
Find the mean of the distribution shown.
x 2 3 4
P(x) 0.30 0.24 0.46