Question 403246
{{{e^(2x + 6) - 8 = 0 }}}
{{{e^(2x + 6)  = 8 }}} take logarithm of both sides of the equation
{{{ln(e^(2x + 6))  = ln8 }}} 
{{{2x + 6  = ln8 }}} 
{{{2x = ln8-6 }}} 
{{{x = (ln8-6)/2 }}} 
{{{x = ln8/2-3 }}} 
{{{x = -1.96 }}}