Question 403215

A) when 2 women and 2 men

no. of ways = 7C2 * 7C2 = 21 *21 = 441


B) a majority of women..

possible cases are...
 4 women, 0 men
 3 women, 1 men

no. of ways = 7C4* 7C0 + 7C3* 7C1 = 35  + 35*7 = 280