Question 403120
{{{ 1/x - 2/x^2-x + 3/x^3-x^2 }}} Common denominator is x^3 so you need to mulitply each one (top and bottom) by what's missing on the bottom
{{{ (1/x)(x^2/x^2) - (2/x^2)(x/x)-x(x^3/x^3) + (3/x^3)-x^2(x^3/x^3) }}} simplify
{{{ (x^2/x^3) - (2x/x^3)-(x^4/x^3) + (3/X^3)-(x^5/x^3) }}} now keep the bottom and combine the tops

{{{ (x^2 - 2x-x^4+3-x^5)/x^3) }}} rearrange terms from largest to smallest
 
{{{ (-x^5-x^4+x^2-2x+3)/x^3) }}} there is nothing else we can do after this point