Question 403159
y=2/3x-1......1
2x+3y=21......2  

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substitute the value of y in second equation

2x+3(2x/3-1)=21
LCD of the parenthesis is 3
{{{2x+(cross(3))(2x-3)/(cross(3)) =21}}}

2x+2x-3=21

4x-3=21
add 3
4x=24
/4
x=6 
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plug value of x in (1)

y=2/3x-1
y=(2/3)*6 -1
y=3

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