Question 402926
{{{14/(3x)+(x+5)/(3x)}}}
The denominators are the same so we can go ahead and add them. As always, you just add the numerators when adding fractions. So we get:
{{{14+x+5/(3x)}}}
which simplifies to:
{{{(x+19)/(3x)}}}<br>
{{{4/(x+2) - 3/(x+2)}}}
The denominators are the same so we can go ahead and subtract them. As always, you just subtract the numerators when subtracting fractions. So we get:
{{{(4-3)/(x+2)}}}
which simplifies to:
{{{1/(x+2)}}}<br>
{{{3/x + 2/x^2}}}
The denominators are not the same. So we must make then the same before we add. We can turnt he first denominator into {{{x^2}}} if we multiply the numerator and denmominator of that fraction by x:
{{{(3/x)(x/x) + 2/x^2}}}
which gives us:
{{{(3x)/x^2 + 2/x^2}}}
Now we can add:
{{{(3x + 2)/x^2}}}