Question 403004
Graph the Circle
x^2+y^2+4x-2y-20=0 
I get:
(x^2+4x)+(y^2-2y)=20
(x^2+4x+4)+(y^2-2y+1)=20+4+1
(x+2)^2 + (y-1) = 25
-----
(x+2)^+(y-1)^2 = 5^2 
------
Center at (-2,1)
Radius = 5
=====================
Cheers,
Stan H.
===========