Question 402808
3b+2c=46
5c+b=11 
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Rearrange:
3b + 2c = 46
b  + 5c = 11
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Multiply 2nd equation by 3 to get:
3b + 2c = 46
3b + 15c = 33
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Subtract top from bottom and solve for "c":
13c = -13
c = -1
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Solve for "b":
5c+b = 11
5(-1) + b = 11
b = 11+5
b = 16
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cheers,
stan H.
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