Question 402791
Write the standard form of the equation of the line passing through the point 
(4,-1) and perpendicular to the line 4x-y=3.
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Find the slope of the line by putting it in slope-intercept form.  That means solve for y.
4x-y=3
y = 4x-3
slope = 4
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The slope of lines perpendicular is the negative inverse = -1/4
Use y = mx + b and the point to find b
-1 =  (-1/4)*4 + b
b = 0
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y = (-1/4)x + 0 is the line thru the point perpendicular to the given line
y = -x/4
4y = -x
x + 4y = 0 (standard form)