Question 402761
Did you mean 6x^2+7x-20??? Becaues the way you wrote it there's nothing to factor. To solve for x you can either use quadratic formula or complete the square. Formula is easier.

6x^2+7x-20=0
a=6, b=7, c=-20
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-7 +- sqrt( 7^2-4*6*-20 ))/(2*6) }}} 
{{{x = (-7 +- sqrt( 49+480 ))/(12) }}} 
{{{x = (-7 +- sqrt( 529 ))/(12) }}} 
{{{x = (-7 +- 23)/(12) }}}
{{{x = (-7 + 23)/(12)=16/12=4/3}}} 
or
{{{x = (-7 - 23)/(12)=-30/12=-5/2 }}}  
So those are your roots.
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{{{6x^2+7y-20}}}  you can try completing the square on it as well
{{{6x^2+7x-20=0}}}
{{{6x^2+7x=20}}}
{{{6(x^2+7x/6)=20}}} so we need to add (7/12)^2 in order to complete the square. But we have to account for that 6 up front, so in reality we are adding 49/24
{{{6(x^2+7x/6+(7/12)^2)=20+49/24}}}
{{{6(x+7/12)^2=20+49/24}}}
{{{6(x+7/12)^2=480/24+49/24}}}
{{{6(x+7/12)^2=529/24}}} divide each side by 6
{{{(x+7/12)^2=529/144}}} take square root of each side
{{{x+7/12=(+-23)/12}}} subtract 7/12 from each side
{{{x=+23/12-7/12=16/12=4/3}}}
or
{{{x=-23/12-7/12=-30/12=-5/2}}}