Question 43485
{{{9x^2 + 1 = 6x}}}
{{{9x^2 - 6x + 1 = 0}}}
Disciminant: {{{b^2 - 4ac}}} where the from: {{{ax^2 + bx + c = 0}}}
a=9 b=-6 c=1
{{{b^2 - 4ac}}}
{{{(-6)^2 - 4(9)(1)}}}
{{{36 - 36}}}
{{{0}}}
Since the discriminant is zero, there is only one real root.
{{{ graph( 600, 600, -10, 10, -10, 10, 9x^2 - 6x + 1) }}}