Question 402415
D=RT
D=60T FOR THE FIRST CAR.
D=75(T-2) FOR THE SECOND CAR.
60T=75(T-150)
60T=75T-150
60T-75T=-150
-15T=-150
T=-150/-15
T=10 HOURS AFTER THE FIRST CAR LEAVES THEY WILL MEET.
PROOF:
60*10=75(10-2)
600=75*8
600=600
10-2=8 HOURS FOR THE SECOND CAR TO CATCH THE FIRST CAR.