Question 402234
The value(s) of x that would make the denominator zero would be the "excluded" value(s).
{{{3x/(x^2-49)}}} Set the denominator equal to zero and solve for x.
{{{x^2-49 = 0}}} Factor.
{{{(x+7)(x-7) = 0}}} so...
{{{x = -7}}} and {{{x = 7}}} would be the excluded values.