Question 402303
Solve:
{{{3 = (5/x)+(4/x^2)}}} Multiply through by {{{x^2}}}
{{{3x^2 = 5x+4}}} Rewrite as:
{{{3x^2-5x-4 = 0}}} Solve with the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}} and here, a = 3, b = -5, and c = -4.
{{{x = (-(-5)+-sqrt((-5)^2-4(3)(-4)))/2(3)}}} Do the math.
{{{x = (5+-sqrt(25+48))/6}}}
{{{x = (5+-sqrt(73))/6}}}